a car is moving at a velocity of 72km/h. suddenly brakes are appiled so as to stop the car after 10m. find the force exerted by the brakes on the car.(If the total mass of car and passengers is equal to 800 kg)
Answers
Answered by
66
Velocity of the car = 72 km/hr
converting it into m/s
72x 1000
3600
20 m/s is its velocity
mass of the car = 800 kg
equation for force=mass multiplied by acceleration
so we need to find acceleration first
time taken to stop the car = 10 min
t = 10 min = 10 x 60 = 600 s
a=(v-u)/t
a=(0-20)/600
a=-20/600
a=-1/30
now we get
f=800 x -1
30
f=26.6N
converting it into m/s
72x 1000
3600
20 m/s is its velocity
mass of the car = 800 kg
equation for force=mass multiplied by acceleration
so we need to find acceleration first
time taken to stop the car = 10 min
t = 10 min = 10 x 60 = 600 s
a=(v-u)/t
a=(0-20)/600
a=-20/600
a=-1/30
now we get
f=800 x -1
30
f=26.6N
Answered by
26
u= 72km/h = 72x1000/3600
=60m/s
v=0 ( brakes applied)
t= 10min
=.10x60 = 600 sec
mass = 800 kg
F=m(v-u) / t
=800 ( 0-60 ) / 600
=800x-60 / 600
=-4800 / 600
= -80
Therefore ,
F= -80N
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