Math, asked by MohdWakas27, 1 year ago

A car is moving at an average speed of 45whole number5/8 km/hr. How much distance will it cover in 6whole number 3/4 hours?

Answers

Answered by rawatrishabh03
0
Given --
Velocity = 45 8/5 = 232/5 km/hr
Time = 27/4 hrs
Distance = ?
Since --
Distance = Velocity × Time
or,
S = v \: × \: t
Distance(S) = 232/5 × 27/4 = 313.2 kms

Hope it helps.
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