Question

A car is moving at an average speed of 56 3/5 km per hour. How much distance will it cover in 7 1/2 hours


ANSWER IT WITH STEPS PLZ

Answer 1

Given :

• Average speed of the car is $\sf{56\dfrac{3}{5}}$ km/hr
• Time = $\sf{7\dfrac{1}{2}}$ hrs

To Find :

• The distance covered by the car in $\sf{7\dfrac{1}{2}}$ hrs

Solution :

The relation between Speed , distance and time is given by ,

$\star\boxed {\sf{\purple{Speed = \dfrac{Distance}{Time}}}}$

We have ,

• t = $\sf{7\dfrac{1}{2}}$ hrs = $\sf{\dfrac{15}{2}}$ hrs

• S = $\sf{56\dfrac{3}{5}}$ km/hr = $\sf{\dfrac{283}{5}}$ km/hr

By substituting the values ,

$\\ : \implies \sf \: \frac{283}{5} \: km {hr}^{ - 1} = \frac{distance}{ \frac{15}{2} \: hr} \\ \\ \\ : \implies \sf \: distance = \frac{15}{2} \: hr \times \frac{283}{5} \: km {hr}^{ - 1} \\ \\ \\ : \implies \sf \: distance = 424.5 \: km$

Hence , The distance covered by the car in $\sf{\dfrac{15}{2}}$ hrs is 424.5 km

Answer 2

Answer:

Given :

Average speed of the car is \sf{56\dfrac{3}{5}}56

5

3

km/hr

Time = \sf{7\dfrac{1}{2}}7

2

1

hrs

To Find :

The distance covered by the car in \sf{7\dfrac{1}{2}}7

2

1

hrs

Solution :

The relation between Speed , distance and time is given by ,

\star\boxed {\sf{\purple{Speed = \dfrac{Distance}{Time}}}}⋆

Speed=

Time

Distance

We have ,

t = \sf{7\dfrac{1}{2}}7

2

1

hrs = \sf{\dfrac{15}{2}}

2

15

hrs

S = \sf{56\dfrac{3}{5}}56

5

3

km/hr = \sf{\dfrac{283}{5}}

5

283

km/hr

By substituting the values ,

\begin{gathered} \\ : \implies \sf \: \frac{283}{5} \: km {hr}^{ - 1} = \frac{distance}{ \frac{15}{2} \: hr} \\ \\ \\ : \implies \sf \: distance = \frac{15}{2} \: hr \times \frac{283}{5} \: km {hr}^{ - 1} \\ \\ \\ : \implies \sf \: distance = 424.5 \: km\end{gathered}

:⟹

5

283

kmhr

−1

=

2

15

hr

distance

:⟹distance=

2

15

hr×

5

283

kmhr

−1

:⟹distance=424.5km

Hence , The distance covered by the car in \sf{\dfrac{15}{2}}

2

15

hrs is 424.5 km