Question

A Car is moving at the rate of 72km/hr. how far does the car move when it stops after 4 second.​

Answer 1

here is the answer of your question

Answer 2

$\Large{\textbf{\underline{\underline{According\;to\;the\;Question}}}}$

u (Initial Velocity) = 72 km/h

u = 72 × 5/18

u = 20 m/s

Also,

v (Final Velocity) = 0 (Because car stops)

t (Time taken) = 4 seconds

Now,

Using 1st Equation of motion,

v = u + at

⇒ 0 = 20 + a × 4

⇒ a = - 5 m/s

Also,

Using 2nd Equation of motion,

⇒ s = ut + 1/2 at²

⇒ s = 20 × 4 + 1/2 × (- 5) × 4²

⇒ s = 80 + 1/2 × (- 5) × 16

⇒ s = 80 + (- 5) × 8

⇒ s = 80 - 40

⇒ s = 40 m.

Therefore,

Distance covered by car = 40 m