A Car is moving at the rate of 72km/hr. how far does the car move when it stops after 4 second.
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here is the answer of your question
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prabhat2000:
40 ans hoga
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u (Initial Velocity) = 72 km/h
u = 72 × 5/18
u = 20 m/s
Also,
v (Final Velocity) = 0 (Because car stops)
t (Time taken) = 4 seconds
Now,
Using 1st Equation of motion,
v = u + at
⇒ 0 = 20 + a × 4
⇒ a = - 5 m/s
Also,
Using 2nd Equation of motion,
⇒ s = ut + 1/2 at²
⇒ s = 20 × 4 + 1/2 × (- 5) × 4²
⇒ s = 80 + 1/2 × (- 5) × 16
⇒ s = 80 + (- 5) × 8
⇒ s = 80 - 40
⇒ s = 40 m.
Therefore,
Distance covered by car = 40 m
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