A car is moving has a velocity of 25 m/s. Brakes are applied so that car comes to rest after travelling a distance of 80m, then acceleration is give solution plese
Answers
Answered by
0
Answer:-
Acceleration of the car = -3.90625 m/s²
Step-by-step explanation:-
Given:-
- A car is moving has a velocity of 25 m/s. Brakes are applied so that car comes to rest after travelling a distance of 80m
To find:-
- Acceleration of the car
Solution:-
As we know,
- v² = u² + 2aS (Third equation of motion)
Where 'v' is the final velocity, 'u' is the initial velocity, 'a' is the acceleration of the body and 'S' is the distance covered by the body.
Now,
v² = u² + 2aS
⇒ 2aS = v² - u²
⇒ a = (v² - u²)/2S
- According to the question, 'v' = 0 (because the car comes to rest), 'u' = 25m/s and S = 80m.
- Put the values
a = [{(0)² - (25)²} / 2(80)] m/s²
⇒ a = [{0 - 625} / 160] m/s²
⇒ a = [-625 / 160] m/s²
⇒ a = -3.90625 m/s²
Hence, acceleration of the car = -3.90625 m/s²
[Note: Acceleration is in negative because the velocity has decreased with time]
More things to know:-
- v = u + at (First equation of motion)
- S = ut + at²/2 (Second equation of motion)
- v² = u² + 2aS (Third equation of motion)
I hope that this helped you :-)
Similar questions