Question

a car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s A pendulum bob is suspended from the roof of the car by a light rigid rod of length 1 m The angle made by the rod with the vertical is

Answer 1

The centripetal acceleration provides a centrifugal force to the bob in the horizontal direction, causing it to get an acceleration in horizontal direction which is equal to V2/R = 10 m/s2.
Gravity acts downwards = 10 m/s2.

Net resultant acceleration vector is 10 x (2)½ m/s2.
This vector makes an angle 45o with vertical since the accelerations in X and Y direction are equal.

Answer 2

Answer:

45

Explanation:

from figure,

`Tcostheta = mg`…………….(i)

or `Tsintheta = (mv^(2))/r`………………..(ii)

Dividing Eq. (ii) by Eq. (i)

`therefore` tantheta = v^(2)/(rg)=(10^(2))/(10xx10)=1`

`rArr theta=45^(@)`