Question

A car is moving in a circular horizontal track of radius of 10m with a constant speed of 10m/s a plumb bob is suspended from the roof of the car by light rigid rod of length 1m the angle made by the rod with track is g=10m/second square

Answer 1

The centripetal acceleration provides a centrifugal force to the bob in the horizontal direction, causing it to get an acceleration in horizontal direction which is equal to V2/R = 10 m/s2.

Answer 2

Answer:

The angle made by the rod with track is 45°.

Explanation:

Given that,

Radius of track = 10 m

Speed = 10 m/s

Length = 1 m

We need to calculate the angle

According to figure,

$T\sin\theta=\dfrac{mv^2}{r}$.....(I)

$T\cos\theta=mg$....(II)

Divided equation (I) by(II)

$\tan\theta=\dfrac{v^2}{gr}$

Put the value into the formula

$\tan\theta=\dfrac{10^2}{10\times10}$

$\theta=45^{\circ}$

Hence, The angle made by the rod with track is 45°.