Question

A car is moving in a circular track of radius 40 m with a constant speed of 20 m/s. A plumb bob is suspended from roof of the car by a string of length
1 m. The angle made by the string with vertical is (g= 10m/s2)
(A) 45 °
(B) 30 °
(C) 60°
(D) 0°​

Answer 1

Answer:

Hence from the figure,

We know that,

Tsinθ=

r

mv

2

[centripetal] ⟶(i)

Tcosθ=mg⟶(ii) (force)

from (i) and (ii))

Tcosθ

Tsinθ

=

r

mv

2

×

mg

1

tanθ=

rg

v

2

Given that, radius =10 m

velocity =10 m/s

g=10m/s

2

tanθ=

10×10

10

2

=1⇒

θ=45

0

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