A car is moving in a circular track of radius 40 m with a constant speed of 20 m/s. A plumb bob is suspended from roof of the car by a string of length
1 m. The angle made by the string with vertical is (g= 10m/s2)
(A) 45 °
(B) 30 °
(C) 60°
(D) 0°
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Answer:
Hence from the figure,
We know that,
Tsinθ=
r
mv
2
[centripetal] ⟶(i)
Tcosθ=mg⟶(ii) (force)
from (i) and (ii))
Tcosθ
Tsinθ
=
r
mv
2
×
mg
1
tanθ=
rg
v
2
Given that, radius =10 m
velocity =10 m/s
g=10m/s
2
tanθ=
10×10
10
2
=1⇒
θ=45
0
Hope it helps Mark as brainlliest pls plspls
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