A car is moving in a straight line with acceleration 3m/s ^2. If initial velocity of car is 2m/s then find:-
1} Velocity of car at t=5 second.
2} Distance travelled by car in first 5 second
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Explanation:
1) as we know v = u + at
where, u = 2m/s ,a = 3m/s² and t = 5s
so v = 2 + (3×5)
= 2 + 15
= 17 m/s
2) S= ut+1/2at²
= 2×5+1/2×3×25
= 10+75/2
95/2 m or 47.5 m
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