Question

A car is moving in a straight road with uniform acceleration.The following table give the speed of mass and different in distance.Plot the velocity graph for relation 0-5 10-10 20-15 30-20 40-25 50-30
Calculate
a)The velocity of the object at the end of 40 sec
b)Acceleration of the object
c)Distance by the car in 50 sec

Answer 1

Answered

A car is moving on a straight road with uniform acceleration.the following table gives the speed of the car at various instant of Time:0-5,10-10,20-15,30-20,40-25,50-30.draw the speed time graph choosing a convenient scale. Determine from it(i) the acceleration of the car (ii)the distance travelled by the car in

Answers

rocky2003

rocky2003 Ambitious

Graph of the table : Draw X - axis and Y - axis on the graph with appropriate scale.

Let 1 cm = 10 s on X-axis.

Let 1 cm = 5 m on Y-axis.



(i) Acceleration means slope of graph AB

BC / AC = 30 - 5 / 50 - 0 = 25 / 30 = 0.5 m / s2

(ii) Distance travelled by car = Area of trapezium OABD

= 1 /2 (AO + BD) × OD

= 1 / 2 (5 + 30) × 50 = 875 m

Answer 2

Such a big question