Question

A car is moving in such way that the distance it covers, is given by the equation S= 4t^2 +3t where S is in meters and t is in second . what would be the velocity and the acceleration of the at time t=20 seconds.... plzzzz ans This question with correct explaination​

Answer 1

Step-by-step explanation:

S = 10 m

hope it's help you ✌

uh apply this.....

v = dx/dt = 4t²+3t

S - 0 = 4+6

S = 10 m

Answer 2

The velocity and acceleration of the car at t = 20 seconds will be 163 m/s and 8 m/s² respectively.

Given,

A car is moving in such a way that the distance it covers, is given by the equation S= 4t²+3t.

To Find,

The velocity and the acceleration of the car at time t = 20 seconds.

Solution,

The velocity and acceleration of an object at a particular instance are given as v = ds/dt and a = dv/dt, where s is the displacement of the object and v is the velocity.

The displacement is given as

s = 4t²+3t

Now, the velocity of the car at t = 20 sec will be

v = ds/dt = d(4t²+3t)/dt

v = 8t+3 = 8(20)+3 = 163 m/s

Now, the acceleration at t = 20 sec will be

a = dv/dt = d(8t+3) = 8 m/s²

Hence, the velocity and acceleration of the car at t = 20 seconds will be 163 m/s and 8 m/s² respectively.

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