A car is moving on a circular path and takes a turn. If R, and R₂ be the reactions on the inner and outer wheels respectively then
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Explanation:
Correct option is
B
R
1
<R
2
The weight Mg of the car acts vertically decreases through the center of gravity G of the car
∴R
1
+R
2
=Mg
and the horizontal force F provides the centripetal force for motion in a circle
∴F=
r
mv
2
Taking moments about G, there should be no resultant turning effect about the center of gravity
Fh+R
1
a=R
2
a
∴R
2
=
a
Fh+R
1
a
or,R
2
=R
1
+(
a
Fh
)
⇒R
2
>R
1
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