Question

a car is moving on a level road and get its velocity doubled in this process how would the kinetic energy of the car change?

please explain every step pls

please don't give silly answers


pls answer fast tomorrow is my exam

Answer 1

kinetic energy = 1/2 ×m×v^2
so if velocity will be doubled than K.E. will becomes 4 times

let initially K.E. be = 1/2×m×v^2
n finally be = 1/2×m×(2v)^2 = 1/2 ×m×4v^2
on dividing both
(K.E)1/(K.E.)2 =1/4
so, K.E.2 = 4K.E.1

if it seems to be helpful mark my answer as brainliest.