Question

A car is moving on a levelled road and gets its velocity doubled.In this process : 1 how would kinetic energy of car changes? 2 how would potential energy of car will change? 3 how will momentum change ?give reasons PLS FAST

Answer 1

Answer:

(i) The potential energy of the car remains same, since PE (= mgh) is independent of velocity.

(ii) The kinetic energy of the car becomes four times, since KE(=1/2 m*v^2) is proportional to square of velocity.

(iii) The momentum of the car will also get doubled, since momentum (p = mv) is proportional to velocity.

Explanation:

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Answer 2

Given ;

Car is moving on a levelled road and gets its velocity doubled.

To Find :

(1) how would kinetic energy of car changes?

(2) how would potential energy of car will change?

(3 )how will momentum change ?

Solution :

(1) Kinetic Energy (KE) = $\frac{1}{2} mv^{2}$

                       KE        $\alpha$   v²

or,               $\frac{KE_{initial}}{KE_{Final} }$    = $(\frac{v}{2v} )^{2}$

or,              $\frac{KE_{initial}}{KE_{Final} }$     = $\frac{v^{2} }{4v^{2} }$

∴              $KE_{Final}$         = 4 $KE_{initial}$

When the velocity doubles, the kinetic energy would increase by (2)² or 4 times.

(2) Potential Energy (PE) is inversely related to Kinetic energy (KE)

As Kinetic energy is increasing, Potential Energy will decrease.

(3) As we know the formula for momentum is :

                              p=mv

Where,

p denotes as the momentum of the body

m denotes the mass of the body

v denotes the velocity

                        Momentum (p) $\alpha$ Velocity (v)

or,                          $\frac{p_{initial} }{p_{final} }$         = $\frac{v}{2v}$

or,                       $p_{final}$             = 2 × $p_{initial}$

∴ When the velocity get doubled, Momentum gets also doubled.