Physics, asked by dishu3548, 1 year ago

a car is moving on a road at a velocity of 36km/h.on applying Breaks it's velocity become 18km/h in 5s.calculate acceleration and distance travelled in 5s​

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Answered by sankalpvyas04
0

Answer:

u=36 km/hr=36×(5/18)=10 m/s

v=18 km/h=18×5/18=5 m/s

t=5 sec

a=v-u/t

=5-10/5

=-5/5

=-1m/s^2

s=ut+1/2at^2

=10×5+1/2 × -1×25

=50-12.5

=37.5m


sankalpvyas04: are you satisfied
Answered by Surajsah977
0

Given above is the answer of your question.

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