A car is moving on a straight road at a speed of 20 m/s . The coefficient of friction between the tyres of the car and the road is 0.4 . Find the shortest distance within which the car can be stopped.
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initial Velocity =20 m/s
friction = 0.4 m/s²
final velocity =0
time taken Will be
a= (v-u)/t
t=(v-u)/a
t= -20/-0.4
t= 50s
s =ut +at²/2
s= 20*50 + 0.4*50*50/2
s = 100+500
s= 600m
friction = 0.4 m/s²
final velocity =0
time taken Will be
a= (v-u)/t
t=(v-u)/a
t= -20/-0.4
t= 50s
s =ut +at²/2
s= 20*50 + 0.4*50*50/2
s = 100+500
s= 600m
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