A car is moving on a straight road at a speed of 20m/s . The coefficient of friction between the tyres of the car and road is 0.4 . Find the shortest distance within which the car be stopped.
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Answer:
50 m
Explanation:
The stopping distance is given by
- S = u²/(2μg)
S = (20 m/s)²/(2 × 0.4 × 10 m/s²)
= (400 m²/s²) / (8 m/s²)
= 50 m
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