A car is moving on a straight road at speed of 20 m/ sec The co efficient of friction between the tyres of car and road is 0.4 find the shortest distance within which car can be stopped ( g 1p m/ s ^2)
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4 m is this right I am not sure
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S = u² / (2μg)
= (20 m/s)² / (2 × 0.4 × 10 m/s²)
= 50 m
The shortest distance within which car can be stopped is 50 m
= (20 m/s)² / (2 × 0.4 × 10 m/s²)
= 50 m
The shortest distance within which car can be stopped is 50 m
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