A car is moving on a straight road with a speed of 108 kilometre per hour is brought to stop with the distance of 150m.Find the retardation
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Answer:
retardation = 3 m/sec²
Explanation:
speed of car, u = 108km/h
= 108*(5/18)m/sec
= 30m/sec
after car is stopped, v = 0 m/sec
distance covered by the car, s = 150m
using, v² = u²+2as
after putting values,
0 = 30²+2*(a)*150
300*a = -900
a = -3m/sec²
therefore retardation =3 m/sec²
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