A car is moving on a straight road with speed v0.If coefficient of friction is mu.The shortest distance in which car is stopped
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From energy conservation / work energy theorem we get,
0.5mv^2 = f x y
0.5mv^2 = umgy
we get,
y = v^2/2ug meter.
0.5mv^2 = f x y
0.5mv^2 = umgy
we get,
y = v^2/2ug meter.
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