A car is moving on a straight road with uniform acceleration.the following table gives the speed of the car at various instant of Time:0-5,10-10,20-15,30-20,40-25,50-30.draw the speed time graph choosing a convenient scale. Determine from it
(i) the acceleration of the car (ii) the distance travelled by the car in 50sec
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Graph of the table : Draw X - axis and Y - axis on the graph with appropriate scale.
Let 1 cm = 10 s on X-axis.
Let 1 cm = 5 m on Y-axis.

(i) Acceleration means slope of graph AB
BC / AC = 30 - 5 / 50 - 0 = 25 / 30 = 0.5 m / s2
(ii) Distance travelled by car = Area of trapezium OABD
= 1 /2 (AO + BD) × OD
= 1 / 2 (5 + 30) × 50 = 875 m
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