A car is moving on a straight road with uniform acceleration. The following table gives the speed of the car at various instants of time. Speed (m/s): 19. 5, 20. 10, 21. 15 ,22. 20, 23. 25 ,24. 30 Time (s): 25. 0, 26. 10 ,27. 20, 28. 30 ,29. 40 ,30. 50 Draw the speed-time graph and determine from it i) acceleration of the car, and (ii) distance traveled by the car in 50 s.
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Let 1 cm = 10 s on X-axis.
Let 1 cm = 5 m on Y-axis.

(i) Acceleration means slope of graph AB
BC / AC = 30 - 5 / 50 - 0 = 25 / 30 = 0.5 m / s2
(ii) Distance travelled by car = Area of trapezium OABD
= 1 /2 (AO + BD) × OD
= 1 / 2 (5 + 30) × 50 = 875 m
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