A car is moving on a straight road with uniform acceleration. The following table gives the speed of the car at various instants of time. Speed (m/s): 19. 5 20. 10 21. 15 22. 20 23. 25 24. 30 Time (s): 25. 0 26. 10 27. 20 28. 30 29. 40 30. 50 Draw the speed-time graph and determine from it i) acceleration of the car, and (ii) distance traveled by the car in 50 s.
Answers
Answer:Graph of the table : Draw X
Answer:Graph of the table : Draw X - axis and Y - axis on the graph with appropriate scale.
Let 1 cm = 10 s on X-axis
. Let 1 cm = 5 m on Y-axis.
(i) Acceleration means slope of graph AB BC / AC = 30 - 5 / 50 - 0 = 25 / 30 = 0.5 m / s2
(ii) Distance travelled by car = Area of trapezium OABD = 1 /2 (AO + BD) × OD= 1 / 2 (5 + 30) × 50 =
875 m
Answer:
875 m
Explanation:
Graph of the table : Draw X - axis and Y - axis on the graph with appropriate scale.
Let 1 cm = 10 s on X-axis.
Let 1 cm = 5 m on Y-axis.
(i) Acceleration means slope of graph AB
BC / AC = 30 - 5 / 50 - 0 = 25 / 30 = 0.5 m / s2
(ii) Distance travelled by car = Area of trapezium OABD
= 1 /2 (AO + BD) × OD
= 1 / 2 (5 + 30) × 50 = 875 m
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