A car is moving on a straight road with uniform acceleration. The velocity of the car varies with time as follows: Time (s) : 0 2 4 6 8 10 Velocity (m/s) : 4 8 12 16 20 24 Draw the velocity -time graph by choosing a convenient scale. From this graph: (i) Calculate the total displacement travelled by the car. (ii) Acceleration of the car in the time interval 4s to 6s.
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Answer:
(i) Acceleration of the car = slope of AB=
10−0
24−4
=
10
20
=2m/s
2
(ii) Distance travelled by the car in 10s= area of trapezium OABC
=
2
1
×(OA+BC)×OC
=
2
1
×(4+24)×10=140m
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