A car is moving on road with a velocity of 100 metre second brake apply and deaccelerator produce of 5 metre per second for 15 seconds find the velocity
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Velocity of moving vehicle=v
0
and decceleration =a
Final velocity of the vehicale =0 (As it stops)
Let the stopping distance be s
Then applying the third equation of motion we have:
v
2
=v
0
2
+2(−a)s
⇒0=v
0
2
−2as
⇒s=
2a
v
0
2
→ Expression for stopping distance.
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