a car is moving on straight road with 126km/hr speed is brought to stop in 200 m. what is the uniform retardation and how long does it take for car to stop
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Answered by
1
V^2=U^2 - 2as
a = 3.0625m/sec^2
v = u - at
t = 11.437 second
a = 3.0625m/sec^2
v = u - at
t = 11.437 second
Answered by
2
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Initial velocity of the car, u = 126 km/h = 35 m/s
Final velocity of the car, v = 0
Distance covered by the car before coming to rest, s = 200 m
Retardation produced in the car = a
From third equation of motion, a can be calculated as:
V^2 - U^2 = 2aS
(0)^2 - (35)^2 = 2 . a . 200
a = ( 35×35)/(2× 200)
a= 3.06 m/ s^2
From first equation of motion, time (t) taken by the car to stop can be obtained as:
V = U + at
t = (V- U )/a = (-35)/(-3.06) = 11.44 sec
I hope, this will help you
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