Question

A car is moving towards north and covers a distance 10 km then it moves towards east and also covers a distance of 10 km . Find a displacement between its initial and final positions.​

Answer 1

Answer:

14.421 metres

Explanation:

Given :

Distance towards North = 10km

Distance towards East = 10km

To find :

Displacement

Here we can just add 10 km and 10km as it would result in the total distance but we need to find the total displacement.

It forms a right angled triangle as it goes 10km north and 10km east

The Hypotenuse will be the Displacement,

Displacement^2 = 10^2 + 10^2

Displacement^2 = 100+100

Displacement^2 = 200

Displacement × Displacement = 200

Displacement = 14.421 m

Answer 2

Explanation:

$\bf \huge \: Question \: \:$

• A car is moving towards north and covers a distance 10 km then it moves towards east and also covers a distance of 10 km . Find a displacement between its initial and final positions.

__________________________

$\bf \huge \: To \: Find \:$

• Find a displacement between its initial and final positions.

__________________________

$\bf \huge \: Given \: \:$

• A car is moving towards north and covers a distance 10 km .
• then it moves towards east and also covers a distance of 10 km .

We Find Displacement :-

According to the Question:-

$\bf\: Displacement^2 = 10^2 + 10^2$

$\bf. we \:know \red {10^2 =100}$

Putting the value :-

$\bf \:Displacement^2 = 100+100\:$

$\bf \:On\: Adding$

$\bf \:Displacement^2 = 200\:$

$\bf \:Displacement = √\:200\:$

Then,:-

$\bf \:Displacement = 14.421 m\:$

Answer is $</u></strong><strong><u>\bf \</u></strong><strong><u>r</u></strong><strong><u>e</u></strong><strong><u>d</u></strong><strong><u>{</u></strong><strong><u>14.421 m\:</u></strong><strong><u>}</u></strong><strong><u>\:$

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