Question

A car is moving with a constant acceleration. At t = 0 s its x is 0 m/s and at 5s its positon is 50m. What is the distance traveled in t=3.5s interval of time, what about the positon if t= 4 minutes

Answer 1

Answer:

A car is moving with a constant acceleration

at t=5s his position = 50m

we know the formula:

$speed = distance \div time$

speed = 50÷5 = 10m/s

the distance traveled in t=3.5s

distance = speed × time

= 10× 3.5

= 35m

his position in t=4minthe distance traveled = 10 × 4 × 60s

= 2400m

Explanation:

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