a car is moving with a speed 20m/s. after it applying break it come at rest 5 second calculate stopping distance
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Answered by
1
Answer:
Explanation:
v=u+at
20=a5
a=4m/s²
v²=u²+2as
20×20=s8
s=400/8
s=25m
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Answered by
0
Answer:
speed,s=20m/s
time, t =5s
distance, d=?
d=s*t
d=20*5
=100m
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