Physics, asked by rutuja6122, 10 months ago

A car is moving with a speed of 10 ms-1 on a circular track of radius 25 m. If its speed is
increasing at the rate of 3 ms-1, its resultant acceleration is
(a) 2.5 ms-1
(b) 5 ms -1
(c) 7.5 ms -1
(d) 10 ms-1​

Answers

Answered by chrissajiphilip
1

Answer:

if it helps PLEASE MARK IT AS BRAINLIEST

Explanation:

Tangential acceleration:at  

=3m/s    

Centripetal acceleration:ar

=  v^2/r

=100/25=4  

∴ Net acceleration  =√3^2+4^2

=5 ms^-1

Answered by Pkush
2

Answer:

5 \: m \: per \: {s}^{ - 2}

Explanation:

centripetal \: acceleration =  {v}^{2}  \div r \\ 10 \times 10 \div 25 = 4 {m}^{ - 2}  \\ tengential \: acc = 3 {m}^{ - 2}  \\ centipetal \: and \: tengential \: acc \: are \: perpendicular \: to \: each \: other \\  so \: resulant =  \sqrt{{4}^{2} +  {3}^{2}  }  = 5 m{s}^{ -2}

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