a car is moving with a speed of 15kmh and another identical car is moving with a speed of 30 kmh. compare their kinetic energy.
plz answer asap it is physics and from the chapter energy and I am in 8th
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Answer:
K1 = (m/2)v12
K1 = (m/2)v12K2 = (m/2)v22
K1 = (m/2)v12K2 = (m/2)v22K2/K1 = (v2/v1)2 = (30/15)2 = 4
K1 = (m/2)v12K2 = (m/2)v22K2/K1 = (v2/v1)2 = (30/15)2 = 4Since both have the same mass, the car moving at twice the speed (i.e. the 30 km/h car) has 4 times the kinetic energy as the other car (the 15 km/h car).
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