Question

A car is moving with a speed of 20m/s. Breaks are applied to produce an acceleration of -2 m/s2. What distance will it cover before coming to stop?

Answer 1

Answer:

displacement =100m

Explanation:

The initial speed of the car 'u'= 20m/s

Acceleration produced 'a'=-2m/s^2

The final velocity 'v' = 0 m/s

applying 3rd eqn of motion

$v^{2} -u^{2} =2ax$

where x is the displacement

(0)^2 - (20)^2 =2(-2)x

-400 = -4x

x=100

therefore the displacement =100m

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