A car is moving with a speed of 30 metre per second on a circular path of radius 500 its speed is increasing at the rate of 2 metre per second square the acceleration the car is
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Answer:
GIVEN THAT A CAR IS MOVING WITH SPEED 30m/s ON A CIRCULAR PATH OF RADIUS 500M . AND THE
SPEED OF CAR IS INCREASING AT RATE OF 2m/s^2 .
THERE FOR WE HAVE
SPEED OF CAR OR (VELOCITY AT FIXED MOMENT) = 30m/s
RADIUS OF TRACK = 500M
ACCELERATION = ??
NOW IN THIS CASE THERE IS TWO TYPES OF ACCELERATION THEY ARE
CENTRIPETAL ACCELERATION WHICH IS
\frac{ {v}^{2} }{radius}
radius
v
2
THAT IS EQUAL TO
\frac{ {30}^{2} }{500} = 1.8
500
30
2
=1.8
NOW SECOND ACCELERATION IS TANGENTIAL
THAT IS EQUAL TO
= 2m/s
NOW THE TOTAL ACCELERATION OR NET ACCELERATION IS
= √[ CENTRIPETAL ACCELERATION + TANGENTIAL ACCELERATION ]
WHICH IS EQUAL TO
\sqrt{ {1.8}^{2} + {2}^{2} } \: = \: 2.69 \: meter \: per \: second \: sqr
1.8
2
+2
2
=2.69meterpersecondsqr
HENCE THE TOTAL ACCELERATION IS
= 2.69 m/s^2
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