Question

A car is moving with a speed of 36ka/h .It stopped in 10 sec after applying brakes .Calculate the acceleration of the car





Answer me plz I dont have too much time




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Answer 1

Answer:

Average speed after brakes applied is (36/2)km/hr = 5m/sec.,

Therefore distance travelled in 2 secs = 10metres.

Retardation is (-10m/sec^2)/2 = -5m/s^2

Explanation:

Hope it will help u

Answer 2

Answer:

Given, Speed=18km/h,t=5s

a)The speed of the car in m/s=18×

18

5

=5 m/s

b) The retardation is:

a=

t

v−u

=

5

0−5

=1m/s

2

c) The velocity of the as a funcition of time 2sis:

v(t)=5−t⇒v(t)=5−2=3m/s=10.8 km/h