A car is moving with a speed of 36kmph
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The displacement in this case be calculated taking the vector represented along north as unit vector j^ and along east as i^. So displacement along north can be found as (36/60)*20=12km. And that along west= {36/60}*25/3= 5km. So the net displacement=sqrt(12^2+5^2)= 13 km. Hence avg velocity=13/{20+8+(1/3)}=13*3/85= 0.458 kmpm. Hence converting this into kmph => 0.458*60 kmph=27.48 kmph.Ans…
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