a car is moving with a speed of 50 kilometre per hour can be stopped by brakes after a distance 6 metre if the same car is moving at a speed of hundred kilometre per hour the minimum stopping distance is
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initial speed of car, u = 50km/h
final speed of car, v = 0
distance covered by car after applying brakes , s = 6m
use formula, v² = u² + 2as
or, 0 = (50km/h)² + 2a(6m)
or, a = -(50km/h)²/2(6m) ......(1)
now, initial speed of particle, u = 100 km/h
final speed of particle , v = 0
we have to find minimum stopping distance, D
use formula, v² = u² + 2aD
or, 0 = (100km/h)² + 2aD
from equation (1),
or, 0 = (100km/h)² + 2{-(50km/h)²/2(6m)}D
or, D = (100km/h)²/{2(500km/h)²/2(6m)}
= 6m × [(100km/h)/(50km/h)]²
= 6m × (2/1)²
= 6m × 4 = 24m
hence, minimum stopping distance is 4m
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