Question

A car is moving with a speed of 54km/hr. What will be the torque

Answer 1

Answer:

Hello Dear.

Given Conditions ⇒

Initial linear velocity(u) = 54 km/hr.

= 54 × 5/18 [Changing into m/s.]

= 15 m/s.

Radius of the wheel(r) = 0.35 m.

Now, Using the Formula,

Initial Angular Velocity (ω₁) = u/r

ω₁ = 15/0.35

ω₁ = 42.86 radian/sec.

Also, Final Angular Velocity (ω₂) = 0

Now, Using the Formula,

Angular Acceleration (α) = (ω₂ - ω₁)/t

= (0 - 42.86)/15

= - 2.86 radian/sec²

Moment of Inertia about the axis of the rotation(I) = 3 kg-m²

∴ Torque = I × α

⇒ Torque = 3 × -2.86

⇒ Torque = -8.58 Nm.

Hence, the average negative torque is -8.58 N-m.

Hope it helps.