A car is moving with a speed of 90 km per hour the driver sees a road sign stating that there is a block in the road in 1 kilometre he applies break to produce an uniform acceleration of -0.5m/s^2 find how for before the block the car stops
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u = 90km/h or 25m/s
2as = v² - u²
2×-0.5×s = 0 - 625
-s = -625
s = 625m
2as = v² - u²
2×-0.5×s = 0 - 625
-s = -625
s = 625m
sunmishgar:
Thank you very much
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