a car is moving with a uniform velocity of 10 m s^-1.the driver of the car decided to overtake a bus moving a head of the car. show the driver of the car accelerates at 1ms^2for 10 seconds find the velocity of the car the end of 10 second also find the distance travelled by the car while acceleration.
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Solution :-
As per the given data ,
- Initial velocity = 10 m/s
- Acceleration = 1 m/s ²
- Time taken = 10 s
As the car is moving with uniform acceleration throughout it's motion , we can use the first equation of motion in order to find final velocity and second / third equation of motion in order to find distance
As per first equation of motion ,
⇒ v = u + at
here ,
- v = final velocity
- u = initial velocity
- a = acceleration
- t = time
⇒ v = 10 + 1 x 10
⇒ v = 20 m / s
The final velocity of the car is 20 m/s
As per second equation of motion ,
⇒ s = ut + at² / 2
here ,
- s = distance
- u = initial velocity
- a = acceleration
- t = time
⇒ s = 10 x 10 + 1 x 100 / 2
⇒ s = 100 + 50
⇒ s = 150 m
The distance traveled by the car is 150 m
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