A car is moving with a uniform velocity of 10 m/s. The driver of the car decides to overtake the bus moving ahead of the car. So the driver of the car accelerate at 1m/s2 for 10 sec. Find the velocity of the car at the end of 10 sec. Also find the distance travelled by car while accelerating
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Given that:
u = 10 m\s
a = 1 m\s
t = 10 s
final velocity, v = ?
We know, v = u +at
=> v = 10 + (1×10)
=> v = 10 + 10
=> v = 20
So, the final velocity is 20 m\s.
Again,
distance, s = ut + (1\2) at²
=> (10×10) + {(1\2)× 1 ×10²}
=> 100 + 50
=> 150
So, the distance is 150 m.
u = 10 m\s
a = 1 m\s
t = 10 s
final velocity, v = ?
We know, v = u +at
=> v = 10 + (1×10)
=> v = 10 + 10
=> v = 20
So, the final velocity is 20 m\s.
Again,
distance, s = ut + (1\2) at²
=> (10×10) + {(1\2)× 1 ×10²}
=> 100 + 50
=> 150
So, the distance is 150 m.
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