a car is moving with a uniform velocity of 10 metre per second the driver of the car decided to take the bus moving ahead of the car so the driver of the car accelerated at one metre per second square for 10 seconds find the velocity of the car at the end of 10 second also find the distance travelled by the car while accelerating
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s=ut+1/2at square
10×10+1/2×1×10 square
5100
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The initial velocity is 10m/s.
S=ut+1/2a(t)^2
S=10×10+1/2×1×(10)^2
S=150
Now, the final velocity will be
V^2 = u^ 2 + 2 a s
V×V = 100 + 300
V × V = 400
So the final velocity is 20 m/s
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