A car is moving with a uniform velocity of 10m/s. The driver of the car decides to overtake the bus moving ahead of the car. So the driver of the car accelerates at 1m/s2 for 10 sec. Find the velocity of the car at the end of 10 sec. Also find the distance travelled by the car while accelerating.
Answers
So the distance travelled by the body is
= 10 × 10 + 0.5 × 100
= 100 + 50
= 150
.now the final velocity will be
V^2 = u^ 2 + 2 a s
V×V = 100 + 300
V × V = 400
So the final velocity is 20 m/s
Answer:
Distance traveled during accelerating exists at 150 m and the final velocity is 20m/sec.
Explanation:
Velocity is a vector quantity. It exists the rate of change in distance. It exists the rate of change of displacement. The speed of an object moving can never be negative. The velocity of a moving object can be zero.
It is given that
u = 10 m/sec
a = 1 m/sec²
t = 10 secs
final velocity = v = ?
Applying the equation,
v = at + u
= (1 m/.sec² × 10 sec) + 10 m/sec
= 10 m/s + 10 m/sec
We get,
= 20 m/sec
so, final velocity = 20 m/sec
now, for computing distance traveled by the car during accelerating :-
Here,
u = 10 m/sec
t = 10 sec
a = 1 m/sec²
distance traveled = ut + 1/2 × at²
= 10 × 10 + 1/2 × 1 × 100
= 100 + 50
We get,
= 150 m
so, distance traveled during accelerating exist 150 m.
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