Question

a car is moving with a velocity 12m/s and stops within 5s find its retardation.​

Answer 1

u=12m/s

v=0m/s(final velocity is zero because it will be at rest after stopping

t=5s

a=v-u/t

$a = \frac{v - u}{t}$

$a = \frac{0 - 12}{5}$

$a = \frac{ - 12}{5}$

$a = - 2.5m$

therefore retardation is -2.5m/s^2