Question

A car is moving with a velocity of 108km/hr and take 6seconds to stop after the breaks applied. Calculate the force exerted by the breaks, if mass is 500kg

Answer 1

u = 108m/s
so 108*5/18 = 30m/s
t = 6 sec
v= 0

a = v-u/t

a = -30/6

a = -5m/s^2

so f = ma

f = 500*(-5)

f = -2500N

so the break exert 2500N forece in opposite direction

Answer 2

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