Physics, asked by naazsamiyah819, 7 months ago

A car is moving with a velocity of 15 m/s. Brakes are applied and the car takes 4s to stop. Find the
retardation and the distance travelled after the application of brakes.​

Answers

Answered by sumansharma9402
0

Answer:

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11th

Physics

Motion in a Straight Line

Stopping Distance and Reaction Time

A car is moving with a velo...

PHYSICS

A car is moving with a velocity of 10 m/s. The driver sees a wall ahead of him and applied brakes. The car stops after covering 10 m distance. If the car was moving with a speed pf 20 ms

−1

, it would have stopped in 30 m distance. The reaction of the driver is

MEDIUM

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ANSWER

Case I. Suppose reduction time = t , so = 10 meters

then distance in t sec will be 10t meter

⇒ remaining distance = 10 meter - 10 t

using v

2

=u

2

−2as

we get s=

2a

u

2

−v

2

=

2a

(10)

2

−0

=

a

50

a

50

=10−10t _______ (1)

Case II

u=20 m/s & S

0

=30 meter

distance in t sec will be 20 t meter

distance during retardation S=

2a

u

2

−v

2

=

2a

(20)

2

−0

S=

a

200

S

0

=30m⇒

a

200

+20t=30

a

50

+5t=7.5 _______ (2)

using (1)

a

50

+10t=10

- - -

___________________

0-5t= -2.5 ⇒ subtracting t=0.5 second

solution

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