Question

A car is moving with a velocity of 16m/s when beakrs are applied. the force applied by the brake is 1000n .the mass of the car alogn with its passengers is 1200kg how long should the brakes be applied ​

Answer 1

Answer:

Explanation:

given that, Vi=16 m/s

and to stop the car final velocity should be zero therefore Vf=0,

and we have stopping force F= -1000 N (since, force being acted opposite the speed of the car)

Total mass of the car, m=1200 Kg

therefore by Newtons' second law

net force= mass * acceleration, and acceleration, a=(Vf-Vi)/t, so

-1000 = 1200*(0-16)/t

-1000 = 1200*(-16)/t

1000 = 1200*16/t

1000*t = 1200*16

t = (1200*16)/1000

t=192/10

t = 19.2 seconds

The brake should be applied for 19.2 seconds in order to stop the car.

have a good day

Answer 2

Explanation:

net force= mass * acceleration, and acceleration, a=(Vf-Vi)/t, so

-1000 = 1200*(0-16)/t

-1000 = 1200*(-16)/t

1000 = 1200*16/t

1000*t = 1200*16

t = (1200*16)/1000

t=192/10

t = 19.2 seconds