Question

A car is moving with a velocity of 20 m /sec. the brakes applied to the car produces an acceleration of 6m/second square in the opposite direction of its motion. if the car takes 2s to stop after the application of brakes, calculate the distance traveled during this time

Answer 1

$s = ut + \frac{1}{2} a {t}^{2}$
u=20m/s
t=2 s
a=6m/s^2
$s = 20 \times 2 + 0.5 \times - 6 \times 4 \\ = 40 - 12 \\ = 28m$
Distance travelled=28m