Physics, asked by wintermoon0613, 6 months ago

A car is moving with a velocity of 2m/s. When the driver applied break, it come to rest by 4sec. Calculate the retardation of the car.

Answers

Answered by sahilmishra1916
5

Answer:

As we know,retardation is opposite of acceleration.So,

final velocity= 0m/s

initial velocity=2m/s

Total time= (final - Initial) time

=( 4 - 0)s = 4s

Retardation of the car= (final - initial) velocity/Total time = (0-2)m/s / 4s

=-2/4 m/s^2

= -1/2 m/s^2

Hence the retardation of the car is -1/2m/s^2

Explanation:

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