Physics, asked by jatin79441, 6 months ago

A car is moving with a velocity of 30 m/s. On applying the brakes, the velocity decreases to 15 m/s in 2 s .The acceleration of car is

Answers

Answered by rupsa68
8

Answer:

a=v-u/t

=30-15/2

=7.5m/s2

Answered by soniatiwari214
0

Concept:

Acceleration can be defined as the change in velocity with respect to change in time.

Acceleration can be calculated as,

a = (v-u)/t

Here, t is time, u is initial velocity, and v is final velocity.

Given:

Initial velocity of car, u = 30 m/s

Final velocity of car, v = 15 m/s

Time, t = 2 s

Find:

The acceleration of the car.

Solution:

As acceleration is the change in velocity with respect to change in time. The velocity is decreasing with respect to the time, we can say that the car is deaccelerating.

a = (v-u)/t

a = (15-30)/2

a = -15/2 = -7.5 m/s²

Hence, the acceleration of the car is -7.5 m/s² when the brake is applied.

#SPJ3

Similar questions