A car is moving with a velocity of 30 m/s. On applying the brakes, the velocity decreases to 15 m/s in 2 s .The acceleration of car is
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Answer:
a=v-u/t
=30-15/2
=7.5m/s2
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Concept:
Acceleration can be defined as the change in velocity with respect to change in time.
Acceleration can be calculated as,
a = (v-u)/t
Here, t is time, u is initial velocity, and v is final velocity.
Given:
Initial velocity of car, u = 30 m/s
Final velocity of car, v = 15 m/s
Time, t = 2 s
Find:
The acceleration of the car.
Solution:
As acceleration is the change in velocity with respect to change in time. The velocity is decreasing with respect to the time, we can say that the car is deaccelerating.
a = (v-u)/t
a = (15-30)/2
a = -15/2 = -7.5 m/s²
Hence, the acceleration of the car is -7.5 m/s² when the brake is applied.
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