A car is moving with a velocity of 36 km/h. On applying brakes, it comes to rest in 2 seconds. Calculate the retardation.
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Answered by
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Answer:
Therefore retardation is 2 m/s^2 and the distance covered by the car before coming to rest is 25 m
Step-by-step explanation:
u=36 km/hr
=5/18*36
=10 m/s
v=0
t=5 s
a=(v-u)/t
=(0-10)/5
=-10/5
=-2 m/s^2
S=ut+1/2at^2
=10*5+1/2*-2*5*5
=50-25
=25 m
Answered by
0
Answer:
Therefore retardation is 2 m/s^2 and the distance covered by the car before coming to rest is 25 m.
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